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The error in the measurement of the radius of a sphere is 0.2%. What is the percentage error in the measurement of its surface area?A. `0.2%`B. `0.4%`C. `0.6%`D. `0.8%` |
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Answer» Correct Answer - b Given : `(Deltar)/(r)=0.2%` Area of a sphere `=4pir^(2)` There is no error in `4pi`, as it is a constant. `therefore (dA)/(A)=2(Deltar)/(r)=2xx0.2%=0.4%` |
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