1.

The escape velocities on the surface of two planets of masses m_1 and m_2 and having the radius r_1 and r_2 are v_1 and v_2 respectively, then

Answer»

`v_1/v_2=(m_1r_1)/(m_2r_2)`
`v_2/v_1=m_1/m_2 r_1/r_2`
`v_2/v_1=sqrt(m_2/m_1 r_1/r_2)`
`v_2/v_1=sqrt((m_1r_1)/(m_2r_2))`

ANSWER :C


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