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The escape velocity for a body projected vertically upwards from the surface of Earth is 11"kms"^(-1)If the body is projected at an angle of45^(@) with verical, the escape velocity will be ........ |
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/11-267621" style="font-weight:bold;" target="_blank" title="Click to know more about 11">11</a>/(sqrt(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>))`<br/>`11sqrt(2)`<br/>22<br/>11</p>Solution :Escape velocity does not depends upon the <a href="https://interviewquestions.tuteehub.com/tag/angle-875388" style="font-weight:bold;" target="_blank" title="Click to know more about ANGLE">ANGLE</a> of projection</body></html> | |