1.

The escape velocity for a body projected vertically upwards from the surface of earth is 11kms^(-1). If the same body is projected at an angle of 45^@ with the vertical, the escape velocity will be

Answer»

`11sqrt2 KMS^(-1)`
`22 kms^(-1)`
`11 kms^(-1)`
`11//sqrt(2) kms^(-1)`

Answer :C


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