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The escape velocity for a planet is ve. A particle is projected from its surface with a speed v. For this particle to move as a satellite around the planet,(a) ve/2 < v < ve(b) ve/ √2 < v < ve(c) ve < v < √2ve(d) ve/√2 < v < ve/2 |
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Answer» Correct Answer is: (b) ve/ √2 < v < ve For a satellite orbiting very close to the earth’s surface, the orbital velocity = √Rg (∵ mg = mv2/R). This is equal to the velocity of projection and is the minimum velocity required to go into orbit. Also, the satellite would escape completely and not go into orbit for v ≥ ve. ∴ ve/√2 < v < ve. |
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