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The escape velocity for a planet is ve. A tunnel is dug along a diameter of the planet and a small body is dropped into it at the surface. When the body reaches the centre of the planet, its speed will be(a) ve(b) ve/√2(c) ve/2(d) zero |
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Answer» Correct Answer is: (b) ve/√2 ve = √2Rg At the surface of the planet, Vs = - GM/R At the centre of the planet, Vc = - 3GM/2R 1/2mv2 = m (Vs - Vc) or v2 = 2 GM/R (3/2 - 1) = GM/R =Rg = ve2/2. |
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