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The escape velocity of a body from Earth's surface isv_(e ). What will be the escape velocity of the same body from a height equal to 7R from Earth's surface. |
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Answer» Solution :`v_(E) prop 1/(sqrt(r))`WHERER is the POSITION of bodyfrom the SURFACE . ` (v_(e))/(v.) = sqrt((r.)/r ) = sqrt((R+7R)/R ) = sqrt((8R)/R ) = sqrt(8) = 2sqrt(2)` ` :. v. = (v_(e))/(2sqrt(2))` |
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