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The escape velocity of projectile on the surface of earth is 11.2 Kms^(-1). If a body is projected out with thrice of this speed, find the speed of the body far away from the earth. Ignore the presence of other planets and sun. |
Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> = sqrt(v_(p)^(2) - v_(e)^(2)) = sqrt((3V_(e))^(2) - v_(<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)^(2))` <br/> `= sqrt(8 <a href="https://interviewquestions.tuteehub.com/tag/xx-747671" style="font-weight:bold;" target="_blank" title="Click to know more about XX">XX</a> 11.2) = 31.68 kms^(-1)`.</body></html> | |