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The escape velocity of projectile on the surface of earth is 11.2 Kms^(-1). If a body is projected out with thrice of this speed , find the speed of the body far away from the earth . Ignore the presence of other planets and sun.

Answer» <html><body><p></p>Solution :`<a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a>=<a href="https://interviewquestions.tuteehub.com/tag/sqrt-1223129" style="font-weight:bold;" target="_blank" title="Click to know more about SQRT">SQRT</a>(v_p^2-v_e^2)=sqrt((3V_e)^(2)-v_(e)^(2))=sqrt8xx11.2 = 31.68kms^(-1)`.</body></html>


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