The escape velocity of the surface of earth is 11.2 km/s. What would be the escape velocity of the surface of another planet of the samemass but (1^(th))/4 times the radius of the earth ?

The escape velocity of the surface of earth is 11.2 km/s. What would b

1.	The escape velocity of the surface of earth is 11.2 km/s. What would be the escape velocity of the surface of another planet of the samemass but (1^(th))/4 times the radius of the earth ?
Answer» 44.8 km/s 22.4 km/s 5.6 km/s 11.2 km/s Solution :`implies` For surface of earth. `v_e=SQRT((2GM_e)/R_e)= 11.2 (km)/s` For PLANET `v_p = (sqrt(2GM_p))/R_p` mass of planet `M_p=M_e` Radius of planet `R_p = R_e/4` `v_p = sqrt((2GM_e)/(R_e/4)) ` `=2 sqrt((2GM_e)/R_e)` `=2(v_e)` `= 1 (11.2 km//s) ` ` =22.4km//s `