The escape velocity on the surface of earth is 11.2 km/s. What will be its value on a planet having double the radius and eight times the mass of earth?

The escape velocity on the surface of earth is 11.2 km/s. What will be

1.	The escape velocity on the surface of earth is 11.2 km/s. What will be its value on a planet having double the radius and eight times the mass of earth?
Answer» SOLUTION :`implies v_p/v_e=SQRT((2GM_e)/R_p)XX sqrt((R_e)/(GM_e))=sqrt(M_p/M_exxR_e/R_p)` `v_p/v_e=sqrt(8xx1/2)=sqrt4 =2` `:. v_p=2v_e=2 (11.2km//s)= 22.4 (KM)/s`