1.

The excess pressure inside a soap bubble is thrice the excess pressure inside a second soap bubble. What is the ratio of volume?

Answer»

Given,

\(\frac{4S}{r_1}\)\(\frac{3\times4S}{r_2}\)

or r2 = 3r1;

\(\frac{V_1}{V_2}\)\(\frac{(\frac{4}{3})πr^3_1}{(\frac{4}{3})πr^3_2}\) 

= \((\frac{r_1}{r_2})^3\) = \((\frac{1}{3})^3\)\(\frac{1}{27}\)



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