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The excess pressure inside a soap bubble is thrice the excess pressure inside a second soap bubble. What is the ratio of volume? |
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Answer» Given, \(\frac{4S}{r_1}\) = \(\frac{3\times4S}{r_2}\) or r2 = 3r1; \(\frac{V_1}{V_2}\) = \(\frac{(\frac{4}{3})πr^3_1}{(\frac{4}{3})πr^3_2}\) = \((\frac{r_1}{r_2})^3\) = \((\frac{1}{3})^3\) = \(\frac{1}{27}\) |
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