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The excess pressure inside a soap bubble is thrice the excess pressure inside a second soap bubble. What is the ratio between the volume of the first and the second bubble?A. `9:1`B. `1:3`C. `1:9`D. `3:1` |
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Answer» Correct Answer - C Pressure , `P=(4S)/(r)` or `P prop (1)/(r)` `therefore (P_(1))/(P_(2))=(r_(2))/(r_(1))=(3)/(1)" "…(i)` or `r_(2)=3r_(1)` Also `(A_(1))/(A_(2))=(4pir_(1)^(2))/(4pir_(2)^(2))=((r_(1))/(r_(2)))^(2)=((r_(1))/(3r_(1)))^(2)" "`(Using (i)) `=(1)/(9)` |
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