The expansion of unit mass of a perfect gas at constant pressure is sh

1.	The expansion of unit mass of a perfect gas at constant pressure is shown in the diagram. Here(a) a = volume, b = °C temperature(b) a = volume, b = K temperature(c) a = °C temperature, b = volume(d) a = K temperature, b = volume
Answer» Correct Option (c) a = °C temperature, b = volume Explanation: In the given graph line have a positive slop with X-axis and negative intercept on Y-axis. So we can write the equation of line y = mx - c ............(i) According to Charle’s law V_t = V₀/273t + V₀, by rewriting this equation we get t = (273/V₀)V_t - 273 ......(ii) By comparing (i) and (ii) we can say that time is represented on Y-axis and volume in X-axis.

The expansion of unit mass of a perfect gas at constant pressure is shown in the diagram. Here(a) a = volume, b = °C temperature(b) a = volume, b = K temperature(c) a = °C temperature, b = volume(d) a = K temperature, b = volume

Answer»

Correct Option (c) a = °C temperature, b = volume

Explanation:

In the given graph line have a positive slop with X-axis and negative intercept on Y-axis.

So we can write the equation of line y = mx - c ............(i)

According to Charle’s law V_t = V₀/273t + V₀, by rewriting this equation we get

t = (273/V₀)V_t - 273 ......(ii)

By comparing (i) and (ii) we can say that time is represented on Y-axis and volume in X-axis.