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The expected workload of generating a collision is of the order of ____________ executions of Whirlpool.(a) 2^(n/2)(b) 2^(n-1)(c) 2^(n)(d) 2^(2n)I got this question during an interview.The query is from Whirlpool Algorithm in division Message Authentication Codes, Whirlpool Algorithm and Key Management and Distribution of Cryptograph & Network Security

Answer»

The correct ANSWER is (a) 2^(n/2)

The explanation: The EXPECTED WORKLOAD of generating a COLLISION is 2^(n/2).



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