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1. |
the exponent of `15` in `100!,` isA. 48B. 24C. 25D. 23 |
Answer» We have, `15=3xx5` Now, `E_(3)(100!)=48` [See illustration 1] and `E_(5)(100!)=[(100)/(5)]+[(100)/(5^(2))]=20+4=24` `:.` Exponent of 15 in 100!=min (24,48) =24. |
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