1.

the exponent of `15` in `100!,` isA. 48B. 24C. 25D. 23

Answer» We have, `15=3xx5`
Now,
`E_(3)(100!)=48`
[See illustration 1]
and `E_(5)(100!)=[(100)/(5)]+[(100)/(5^(2))]=20+4=24`
`:.` Exponent of 15 in 100!=min (24,48) =24.


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