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The exponent of 7 in `100C_50` is |
Answer» We have, `""^(100)C_(50)=(1000!)/(50!50!)` Now, `E_(7)(100!)=[(100)/(7)]+[(100)/(7^(2))]=14+2=16` and, `E_(7)(50!)=[(50)/(7)]+[(50)/(7^(2))]=7+1=8` Thus, exponent of 7 in `""^(100)C_(50)=16-2xx8=0` |
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