InterviewSolution
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InterviewSolution
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The expression for equilibrium constant, `K_(c)` for the following reaction is `Fe_((aq))^(3+)+3OH_((aq))^(-)hArrFe(OH)_(3(s))`A. `K_(c)=([Fe(OH)_(3)])/([Fe^(3+)][OH^(-)]^(3))`B. `K_(c)=([Fe(OH)_(3)])/([Fe^(3+)][OH^(-)])`C. `K_(c)=(1)/([Fe^(3+)][OH^(-)]^(3))`D. `K_(c)=[Fe(OH)_(3)]` |
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Answer» Correct Answer - C For `Fe_((aq))^(3+)+3OH_((aq))^(-)hArrFe(OH)_(3(s))` `K_(c)=(1)/([Fe^(3+)][OH^(-)]^(3))` |
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