The expression, for p != 1, (1 + p^(256)) xx (1 + p^(128)) xx (1+ p^(6 – InterviewSolution

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1.	The expression, for p != 1, (1 + p^(256)) xx (1 + p^(128)) xx (1+ p^(64)) xx (1 + p^(32)) xx (1 + p^(16)) xx (1 + p^8) xx (1 +p^4)(1 + p^2)(1 + p) is equivalent to :
Answer» `(1+P^256)/(1+p^128)` `(1-P^512)/(1-p)` `(1-P^256)/(1-p)` `p^255` ANSWER :B

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