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The factorisation of 4x2 + 8x + 3 is (A) (x + 1) (x + 3) (B) (2x + 1) (2x + 3) (C) (2x + 2) (2x + 5) (D) (2x –1) (2x –3) |
Answer» (b) (2x+1) (2x + 3) Now, 4x2 + 8x + 3 = 4x2 + 6x + 2x + 3 [by splitting middle term] = 2x(2x+ 3) + 1 (2x+ 3) = (2x + 3) (2x + 1) |
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