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The far point of a myopic eye is at `50 cm`. Calculate the power of the lens to correct his vision. |
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Answer» Here, distance of far point `x = 50 cm, power P = ?` As `f = - x, f = - 50 cm` Thus, power, `P = (100)/(f) = (100)/(-50) = - D` Negative sign indicates that the lens used is concave. |
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