1.

The far point of a myopic eye is at `50 cm`. Calculate the power of the lens to correct his vision.

Answer» Here, distance of far point `x = 50 cm, power P = ?`
As `f = - x, f = - 50 cm`
Thus, power, `P = (100)/(f) = (100)/(-50) = - D`
Negative sign indicates that the lens used is concave.


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