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The favourable conditions for a spontaneous reaction areA. `TDeltaS gt DeltaH`, `DeltaH=+ve`, `DeltaS=+ve`B. `TDeltaS gt DeltaH`, `DeltaH=+ve`, `DeltaS=-ve`C. `TDeltaS = DeltaH`, `DeltaH=-ve`, `DeltaS=-ve`D. `TDeltaS = DeltaH`, `DeltaH=+ve`, `DeltaS=+ve` |
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Answer» Correct Answer - A `DeltaG=DeltaH-TDeltaS`. For a process to be spontaneous, `DeltaG` should be `-ve`. In `(A) DeltaH` is `+ve` and `DeltaS` is `+ve` and `TDeltaS gt DeltaH` `0 gt DeltaH-TDeltaS` `0 gt DeltaG` i.e., process is spontaneous |
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