The field strength due to space wave propagation is E=____(a) \(\frac{4πh_t h_r}{λd^2}E_0\)(b) \(\frac{2πh_t h_r}{λd^2}E_0\)(c) \(\frac{4πh_t h_r}{λd}E_0\)(d) \(\frac{4πh_t h_r}{λd^4}E_0\)The question was asked by my school teacher while I was bunking the class.Question is taken from Radio Wave Propagation in portion Radio Wave Propagation of Antennas

The field strength due to space wave propagation is E=____(a) \(\frac{

1.	The field strength due to space wave propagation is E=____(a) \(\frac{4πh_t h_r}{λd^2}E_0\)(b) \(\frac{2πh_t h_r}{λd^2}E_0\)(c) \(\frac{4πh_t h_r}{λd}E_0\)(d) \(\frac{4πh_t h_r}{λd^4}E_0\)The question was asked by my school teacher while I was bunking the class.Question is taken from Radio Wave Propagation in portion Radio Wave Propagation of Antennas
Answer» The correct OPTION is (a) \(\frac{4πh_t h_r}{λd^2}E_0\) The explanation: Space wave propagation reflects frequencies above 30MHz. The FIELD strength due to space wave propagation is \(E=\frac{2E_0}{d} sin⁡ \frac{2πh_t h_r}{λd} ≈ \frac{4πh_t h_r}{λd^2}E_0\) Here E0 is the field strength due to LOS at a unit distance which depends on transmits power, HT and HR is the HEIGHT of transmitting and receiving antenna and d is the distance between two antennas.

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