The figure shown a pipe of uniform cross-section inclined in a vertical plane. A U-tube manometer is connected between the point A and B. If the liquid of density `rho_(0)` flows with velocity `v_(0)` in the pipe. Then the reading h of the manometer is A. `h=0`B. `h=(v_(0)^(2))/(2g)`C. `h=(rho_0)/(rho)((v_(0)^(2))/(2g))`D. `h=(rho_(0) H)/(rho-rho_(0))`

The figure shown a pipe of uniform cross-section inclined in a vertica

1.	The figure shown a pipe of uniform cross-section inclined in a vertical plane. A U-tube manometer is connected between the point A and B. If the liquid of density `rho_(0)` flows with velocity `v_(0)` in the pipe. Then the reading h of the manometer is A. `h=0`B. `h=(v_(0)^(2))/(2g)`C. `h=(rho_0)/(rho)((v_(0)^(2))/(2g))`D. `h=(rho_(0) H)/(rho-rho_(0))`
Answer» Correct Answer - A From continuity equation, `v_(A)=v_(B)=v_(0)` `:. p_(A)=rhogh=p_(B)+0` `:. p_(B)-p_(A)=rhogh` …(i) Now, let us make pressure equation from manometer. `p_(A)+rho g (h+H)=rho_(Hg) gh=p_(3)` Putting `p_(B)-p_(A)=rhogh we get h=0`.

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