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The figure shows a non conducting ring of radius `R` carrying a charge `q`. In a circular region of radis `r`, a uniform magnetic field `B` perpendicular to the plane of the ring varies at a constant rate `(dB)/(dt)=beta`. The torque on the ring is A. `1/2qr^2beta`B. `1/2qR^2beta`C. `qr^2beta`D. zero |
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Answer» Correct Answer - A `El=(dphi)/(dt)=S(dB)/(dt)` `E(2pir)=(pir^2)(beta)` `:. E=r^2/(2R)betaimplies F=qE` and `tau=FR=qER =1/2qr^2beta` |
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