InterviewSolution
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InterviewSolution
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The figure shows an experimental plot discharging of a capacitor in an `RC` circuit. The time constant of this circuit lies between: A. 150 sec and 200 secB. 0 and 50 secC. 50 sec and 100 secD. 100 sec and 150 sec |
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Answer» Correct Answer - D From Fig. max p.d. `V_(0) = 25` volt Corresponding to `V = (V_(0))/(2) = (25)/(2) = 12.5 V`, `t = 100 s`. The discharging of a capacitor through resistance is governed by `V = V_(0) e^(-t//tau)` when `V = (V_(0))/(2) , (V_(0))/(2) = V_(0) e^(-t//tai)` `log_(e) 1 - log_(e) 2 = - (t)/(tau) log_(e) e = - (t)/(tau)` `tau = (t)/(log_(e) 2) = (100)/(0.693) = 144.3 s` Choice (d) is correct |
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