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The figure shows the interfernece pattern obtained in double slit experiment using light of wavelength 600 nm. Q. Let `DeltaX_(A)` and `DeltaX_(C)` represent path differences between waves interering at 1 and 3 respectively then `(|DeltaX_(C)|-(|DeltaX_(A)|)` is equal to |
Answer» Correct Answer - B `CBFimplies` path difference `=0` `DeltaX_(A)toAt" "1` dark fringe having path difference `=(lamda)/(2)` `DeltaX_(C)to`At 3, bright fringes path difference `=lamda` `therefore(|DeltaX_(C)|-|DeltaX_(A)|)=(lamda-(lamda)/(2))=(lamda)/(2)=(600)/(2)nm=300nm` |
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