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The final product obtained for the following reaction is: `KMnO_(4)("excess") +H_(2)SO_(4)("concentrated and cold") to`A. `Mn_(2)O_(7)`B. `MnO`C. `Mn_(3)O_(4)`D. `MnO_(3)^(+)` |
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Answer» Correct Answer - A `2KMnO_(4)+3H_(2)SO_(4)to2KHSO_(4)+(MnO_(3))_(2)SO_(4)+2H_(2)O` `(MnO_(3))_(2)SO_(4)+H_(2)O toMn_(2)O_(7)+H_(2)SO_(4)` |
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