1.

The final velocity fo a particles falling freelly under graavity is given by `V^(2) - U^(2) = 2GX` WHERE `x` is the distance covered. IF `V = 18` kmph. `g = 1000 cm s^(-2), x = 120 cm` then `u = ...ms^(-1)`A. `2.4`B. `1.2`C. `1`D. `0.1`

Answer» Correct Answer - C
`v^(2) - u^(2) = 2gx` and change into `S.I`


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