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The first and second dissociation constants of an acid `H_(2)A` are `1.0 xx 10^(-5)` and `5.0 xx 10^(-10)` respectively. The overall dissociation constant of the acid will beA. `5.0 xx 10^(-5)`B. `5.0 xx 10^(15)`C. `5.0 xx 10^(-15)`D. `0.0 xx 10^(-5)` |
Answer» Correct Answer - C `H_(2)A hArr HA^(-) + H^(+) " " K_(1) = ([HA^(-)][H^(+)])/([H_(2)A])` ...(i) `HA^(-) rarr H^(-) + A^(2-) " " K_(2) = ([H^(+)][A^(2-)])/([HA^(-)])` ...(ii) For the reaction `H_(2)A hArr 2H^(+) + A^(2-)` `K = ([H^(+)]^(2) [A^(2-)])/([H_(2)A]) = K_(1) xx K_(2)` `= 1 xx 10^(-5) xx 5 xx 10^(-10) = 5 xx 10^(-15)`. |
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