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The first emission line of Balmer series in H spectrum has the wave number equal to :A. `(9R)/(400)cm^(-1)`B. `(7R)/(144)cm^(-1)`C. `(3R)/(4)cm^(-1)`D. `(5R)/(36)cm^(-1)` |
Answer» Correct Answer - D For Balmer series, `n_(1)=2` and `n_(2)=3, 4, 5 .....` `bar(v)`(for first line)`=R[(1)/(2^(2))-(1)/(3^(2))]=R((1)/(4)-(1)/(9))=(5R)/(36) cm^(-1)`. |
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