1.

The first ionisation potentials (eV) of `Be` and `B` respectively areA. `9.32eV,8.29eV`B. `9.32eV,9.32eV`C. `8.29eV,8.29eV`D. `8.29eV,9.32eV`

Answer» Correct Answer - A
First `IP` of `Be gt B` because of stable `ns^(2)` configuration.


Discussion

No Comment Found

Related InterviewSolutions