1.

The first ionizationsenergy of Na is 495.9KJ/mole, what is thelongest wave length oflight that could removean electron from Na?(with proper steps please​

Answer»

ANSWER:

a) 2.41*{10}^{-7}

Explanation:

IONIZATION energy of Na is 495.9KJ/MOLE

1 mole= 495.9KJ

1 atom= 495.9KJ/Na

         = 495.9/6.023*10^23 = hC/λ

λ=\dfrac{6.023*{10}^{23}}{495.9*6.626*{10}^{34}*3*{10}^{8}}

 = 2.41*{10}^{-7}



Discussion

No Comment Found