The first line in any shell script begins with a _____(a) &(b) !(c) $(d) #I got this question in quiz.Question is taken from Shell Programming using read Command and Command Line Arguments topic in portion Essential Shell Programming of Unix

The first line in any shell script begins with a _____(a) &(b) !(c) $(

1.	The first line in any shell script begins with a _____(a) &(b) !(c) $(d) #I got this question in quiz.Question is taken from Shell Programming using read Command and Command Line Arguments topic in portion Essential Shell Programming of Unix
Answer» CORRECT answer is (d) # For EXPLANATION I would say: When the comment character (#) is PLACED anywhere in a line; the shell ignores all characters on its right. However, this rule doesn’t apply to the first line which is the interpreter line. It always begins with #! and FOLLOWED by the pathname of the shell to be used for running the script.

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The first line in any shell script begins with a _____(a) &(b) !(c) $(d) #I got this question in quiz.Question is taken from Shell Programming using read Command and Command Line Arguments topic in portion Essential Shell Programming of Unix

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