Saved Bookmarks
| 1. |
The first overtone frequency of a closed organ pipe P₁ is equal to the fundamental frequency of an open organ pipe P₂. If the length of pipe P₁ is 30 cm, what will be the length of P₂? |
|
Answer» The first overtone frequency of the closed organ pipe ν =3V/4L₁ The fundamental frequency of an open organ pipe ν =V/2L₂ Equating, 3V/4L₁ = V/2L₂ →L₂ = 2L₁/3 {Given L₁ = 30 cm} →L₂ = 2*30/3 cm =20 cm. |
|