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                                    The first overtone frequency of a closed organ pipe P₁ is equal to the fundamental frequency of an open organ pipe P₂. If the length of pipe P₁ is 30 cm, what will be the length of P₂? | 
                            
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Answer»  The first overtone frequency of the closed organ pipe ν =3V/4L₁ The fundamental frequency of an open organ pipe ν =V/2L₂ Equating, 3V/4L₁ = V/2L₂ →L₂ = 2L₁/3 {Given L₁ = 30 cm} →L₂ = 2*30/3 cm =20 cm.  | 
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