1.

The first, second and the last terms of an A.P. are 101, 111 and 2001. Find the number of terms.

Answer»

hey mate here is UR answer

a=101

d=111-101=10

tn=a+(n-1)d

2001=101+(n-1)10

2001=101+10n-10

2001=91+10n

10n=1910

n=191

hence NUMBER of TERMS =191.

hope it helps.



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