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The first, second and the last terms of an A.P. are 101, 111 and 2001. Find the number of terms. |
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Answer» hey mate here is UR answer a=101 d=111-101=10 tn=a+(n-1)d 2001=101+(n-1)10 2001=101+10n-10 2001=91+10n 10n=1910 n=191 hope it helps. ☆☆☆ |
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