The first, second and third class third class train fare is Rs. 15, Rs

1.	The first, second and third class third class train fare is Rs. 15, Rs. 10, and Rs. 7.50 per km respectively. Someday the ratio of numbers travelling in these categories is 2 : 5 : 13. What will be the average fare per passenger for that day?1. Rs. 122. Rs. 103. Rs. 154. Rs. 185. None of the above.
Answer» Correct Answer - Option 5 : None of the above. Given: The first, second and third class third class train fare is Rs. 15, Rs. 10, and Rs. 7.50 per km respectively. The ratio of numbers travelling in these categories is 2 : 5 : 13 Formula used: Average = (Sum of total number)/(Total number of observation) Using the simple concept of ratio. Calculation: Let the number of passenger in someday 2x, 5x and 13x. Total fare by first fare = 15 × 2x = 30x Total fare by first fare = 10 × 5x = 50x Total fare by first fare = 7.5 × 13x = 97.5x Total number of passenger = 2x + 5x + 13x = 20x Total fare = 30x + 50x + 97.5x = 177.5x Average = (Sum of total number)/(Total number of observation) ⇒ Average = (177.5x)/(20x) ⇒ 8.875 ∴ The average fare per passenger for that day is 8.875

The first, second and third class third class train fare is Rs. 15, Rs. 10, and Rs. 7.50 per km respectively. Someday the ratio of numbers travelling in these categories is 2 : 5 : 13. What will be the average fare per passenger for that day?1. Rs. 122. Rs. 103. Rs. 154. Rs. 185. None of the above.

Answer» Correct Answer - Option 5 : None of the above.

Given:

The first, second and third class third class train fare is Rs. 15, Rs. 10, and Rs. 7.50 per km respectively.

The ratio of numbers travelling in these categories is 2 : 5 : 13

Formula used:

Average = (Sum of total number)/(Total number of observation)

Using the simple concept of ratio.

Calculation:

Let the number of passenger in someday 2x, 5x and 13x.

Total fare by first fare = 15 × 2x = 30x

Total fare by first fare = 10 × 5x = 50x

Total fare by first fare = 7.5 × 13x = 97.5x

Total number of passenger = 2x + 5x + 13x = 20x

Total fare = 30x + 50x + 97.5x = 177.5x

Average = (Sum of total number)/(Total number of observation)

⇒ Average = (177.5x)/(20x)

⇒ 8.875

∴ The average fare per passenger for that day is 8.875