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InterviewSolution
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The fission of one nucleus of 92U239 release 200 Mev of energy.1. What is meant by fission2. Express 200 Mev energy in joule3. How many fission of 92U239 should occur per send for producing a power of 1 Mev |
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Answer» 1. The splitting of heavy nucleus into two nucleus is called fission. 2. E = 200 Mev = 200 × 10-6 ev E = 200 × 106 x 1.6 x 10-19J = 3.2 x 10-11J. 3. Number of fission \(n=\frac{Total\,energy}{energy\,per\,fission}\) = \(\frac{1\times10^6}{3.2\times10^{-11}}\) = 3.3 x 1010 |
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