The fix point through which the line `x(a+2b)+y(a+3b)=a+b` always passes for all values of a and b is:

The fix point through which the line `x(a+2b)+y(a+3b)=a+b` always pass

1.	The fix point through which the line `x(a+2b)+y(a+3b)=a+b` always passes for all values of a and b is:
Answer» `x(a+2b)+y(a+3b) = a+b` Here, both positive values of `x` and `y` can not be the answer as it can not make both sides equal. So, we can reject option `(1) and (2)`. We check for third option that is `x = 2, y = -1` Then, `L.H.S. = x(a+2b)+y(a+3b) = 2(a+2b)+(-1)(a+3b)` `=2a+4b - a-3b = a+b = R.H.S.` So, option `(3)` is the correct option. Option`(4)` also can not be the answer as `y = -2`, will make left side negative. So, option `(3)` is the only correct option.

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The fix point through which the line `x(a+2b)+y(a+3b)=a+b` always passes for all values of a and b is:

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