The floor of a hall consists of 290 tiles which are rhombus-shaped and

1.	The floor of a hall consists of 290 tiles which are rhombus-shaped and the length of the diagonals is 39 m and 30 m. What is the total cost of painting the floor at the rate of Rs. 3 per m2?1. Rs. 5089502. Rs. 5089953. Rs. 5089354. Rs. 608945
Answer» Correct Answer - Option 1 : Rs. 508950 Given: Diagonals of the small tiles are 39 m and 30 m Total number of tiles = 290 Rate of painting = Rs. 3 per m2 Formula used: Area of Rhombus = (d1 × d2)/2 Here, d1 and d2 are diagonals of a rhombus Concept used: All sides of a rhombus are equal and diagonals bisect each other at a right angle. Calculation: Area of Rhombus = (d1 × d2)/2 ⇒ Area = (39 × 30)/2 ⇒ Area = 585 m2 Total area of hall’s floor = 585 × 290 = 169650 m2 Cost of painting floor = 169650 × 3 = Rs. 508950 ∴ The cost of painting the floor of the hall is Rs. 508950

The floor of a hall consists of 290 tiles which are rhombus-shaped and the length of the diagonals is 39 m and 30 m. What is the total cost of painting the floor at the rate of Rs. 3 per m2?1. Rs. 5089502. Rs. 5089953. Rs. 5089354. Rs. 608945

Answer» Correct Answer - Option 1 : Rs. 508950

Given:

Diagonals of the small tiles are 39 m and 30 m

Total number of tiles = 290

Rate of painting = Rs. 3 per m2

Formula used:

Area of Rhombus = (d1 × d2)/2

Here, d1 and d2 are diagonals of a rhombus

Concept used:

All sides of a rhombus are equal and diagonals bisect each other at a right angle.

Calculation:

Area of Rhombus = (d1 × d2)/2

⇒ Area = (39 × 30)/2

⇒ Area = 585 m2

Total area of hall’s floor = 585 × 290 = 169650 m2

Cost of painting floor = 169650 × 3 = Rs. 508950

∴ The cost of painting the floor of the hall is Rs. 508950

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