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The flow rate of water from a tap of diameter 1.25cm is 0.48 L/ min . Thecoefficient of viscosity of water is 10^(-3) Pa s . After sometime the flow rate is increased to 3L/min. Characyerise the flowfor both the flow rates . |
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Answer» Solution :Diameter of CROSS section of TAP d= 1.25cm The volume of WATER flowing out per second (flux ) is , `Q=vA` `Q=vxx(pid^(2))/(4) ""[becausevxxpir^(2)]` `thereforev=(4Q)/(pid^(2))` Raynold.s NUMBER `R_(e)=(rhovd)/(eta)=(4rhoQ)/(pietad)` `=(4xx10^(3)xx0.48xx10^(3)xx10^(-6))/(3.14xx10^(-3)xx1.25xx10^(-2)xx60)` `=0.0081528xx10^(5)` `=815` `therefore` For steady flow `R_(e)lt1000` If `Q.=(3L)/(min)=(3xx10^(-3))/(60)=0.5xx10^(-4)(m^(3))/(s)` `thereforeR_(e).=(4rhoQ.)/(pietad)` `=(4xx10^(3)xx0.5xx10^(-4))/(3.14xx10^(-3)xx1.25xx10^(-2))` `=0.5095xx10^(4)` `R_(e)=5095` Hence , `R_(e)gt3000`flow will be turbulent. |
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