1.

The flow rate of water from a tap of diameter 1.25cm is 0.48 L/ min . Thecoefficient of viscosity of water is 10^(-3) Pa s . After sometime the flow rate is increased to 3L/min. Characyerise the flowfor both the flow rates .

Answer»

Solution :Diameter of CROSS section of TAP d= 1.25cm
The volume of WATER flowing out per second (flux ) is ,
`Q=vA`
`Q=vxx(pid^(2))/(4) ""[becausevxxpir^(2)]`
`thereforev=(4Q)/(pid^(2))`
Raynold.s NUMBER `R_(e)=(rhovd)/(eta)=(4rhoQ)/(pietad)`
`=(4xx10^(3)xx0.48xx10^(3)xx10^(-6))/(3.14xx10^(-3)xx1.25xx10^(-2)xx60)`
`=0.0081528xx10^(5)`
`=815`
`therefore` For steady flow `R_(e)lt1000`
If `Q.=(3L)/(min)=(3xx10^(-3))/(60)=0.5xx10^(-4)(m^(3))/(s)`
`thereforeR_(e).=(4rhoQ.)/(pietad)`
`=(4xx10^(3)xx0.5xx10^(-4))/(3.14xx10^(-3)xx1.25xx10^(-2))`
`=0.5095xx10^(4)`
`R_(e)=5095`
Hence , `R_(e)gt3000`flow will be turbulent.


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