1.

The flywheel of an engine, acted upon by a constant torque at the rate of 3000 rev/ min and develops a power of 10 kW. Find the torque acting on the wheel.

Answer»

Solution :`tau ="Power"//2pin = 10 xx 10^(3) xx 60//2 xx 3.14 xx 6000 = 31.82 NM`


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