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The focal length of a convex lens is 50 cm. If an object is kept at a distance of 75 cm from the lens, then find the image distance and magnificationproduced by the lens. |
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Answer» 2FeSO4 ---∆---> 2 FeO + 2 SO2 + O2products obtained - SULPHUR dioxide , iron (II) OXIDE , oxygen gasf=50cmu=75cmv=??1/f = 1/u + 1/v1/50 = -1/75 + 1/v1/v = 1/50 + 1/751/v = 3+2/1501/v = 5/1501/v= 1/30image is formed 30 CM behind the mirrormagnification = -(v/u)M = -(-30/75)M= 30/75= 2/5magnification = +2/5 |
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