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The focal length of an equiconvex lens is equal to radius of curvature of either surface. What is the refractive index of the material of the prism ? |
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Answer» Here, `R_1 = R, R_2 = -R , f = , mu = ?` From `(1)/(f)=(mu -1)((1)/(R_1) - (1)/(R_2))` `(1)/(R ) = (mu - 1) ((1)/( R) + (1)/( R)) = (mu - 1)(2)/( R)` `mu - 1 = (1)/(2)` or `mu = 3//2 = 1.5`. |
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