The following are the steps involved in finding the least amont `sqrt(3),root(3)(4) and root(6)(15)` . Arrange them in sequential order. (A) `therefore root(6)(15)` is the smallest (B) `therefore 3^(1//2)=3^(3//6), 4^(1//3)=4^(2//6), 15^(1//6)=15^(1//6)` (C)The LCM fo the denominators of the exponents is 6 (D) `sqrt(3)=3^(1//2), root(3)(4)=4^(1//3), root(6)(15)=15^(1//6)` (E) `therefore sqrt(3)=root(6)(27), root(3)(4)=root(6)(16)root(6)(15)=root(6)(15)`A. DCABEB. DABEBC. DCBEAD. DBCAE

The following are the steps involved in finding the least amont `sqrt(

1.	The following are the steps involved in finding the least amont `sqrt(3),root(3)(4) and root(6)(15)` . Arrange them in sequential order. (A) `therefore root(6)(15)` is the smallest (B) `therefore 3^(1//2)=3^(3//6), 4^(1//3)=4^(2//6), 15^(1//6)=15^(1//6)` (C)The LCM fo the denominators of the exponents is 6 (D) `sqrt(3)=3^(1//2), root(3)(4)=4^(1//3), root(6)(15)=15^(1//6)` (E) `therefore sqrt(3)=root(6)(27), root(3)(4)=root(6)(16)root(6)(15)=root(6)(15)`A. DCABEB. DABEBC. DCBEAD. DBCAE
Answer» Correct Answer - C DCBEA is the required sequential order.