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The following concentrations were obtained for the formation of NH3from N2 and H2 at equilibrium at 500K. [N2]=1.5×10^−2M,[H2]=3.0×10^−2M and [NH3]=1.2×10^−2M. Calculate equilibrium constant. |
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Answer» -•[H₂] = 3.0 × 10⁻² M.•[N₂] = 1.5 × 10⁻² M.•[NH₃] = 1.2 × 10⁻² M.To Find :-• Equilibrium constant, SOLUTION :-GIVEN REACTION, ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀⠀⠀ |
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