InterviewSolution
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The following configuration of gate is equivalent to A. `NAND` gateB. `XOR` gateC. `OR` gateD. `NOR` gate |
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Answer» Correct Answer - B `Y=(A+B).(overline(A.B))=(A+B).(overline(A)+overline(B))` `=A. overline(A) + A. overline(A) + overline(A).B+ B. overline(B)` `Y=(A.overline(B))+(overline(A).B)`. It is `XOR` gate. |
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