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The following electrochemical cell has been set-up, `Pt(1)|Fe^(3+), Fe^(2+) (a=1)||Ce^(4+), Ce^(3+) (a=1) Pt (2)` `E^(@) (Fe^(3+) //Fe^(2+))=0.77 V, E^(@) (Ce^(4+)//Ce^(3+))=1.61 V` If an ammeter is connected between the two platinum electrodes, predict the direction of flow of current. Will the current increase or decrease with time ? |
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Answer» Current will flow from higher reduction potential electrode to lower reduction potential electrode, i.e., from `Pt(2)` electrode to `Pt(1)` electrode. `E_(cell)^(@)=1.61-0.77=0.84` volt |
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