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The following figures are parallelograms. Find the degree values of the unknowns x, y, z. |
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Answer» (i) ∠ABC = ∠y = 100o (opposite angles are equal in a parallelogram) ∠x + ∠y = 180o (sum of adjacent angles is = 180o in a parallelogram) ∠x + 100o = 180o ∠x = 180o – 100o = 80o ∴ ∠x = 80o ∠y = 100o∠z = 80o (opposite angles are equal in a parallelogram) (ii) ∠RSP + ∠y = 180o (sum of adjacent angles is = 180o in a parallelogram) ∠y + 50o = 180o ∠y = 180o – 50o = 130o ∴ ∠x = ∠y = 130o (opposite angles are equal in a parallelogram) ∠RSP = ∠RQP = 50o (opposite angles are equal in a parallelogram) ∠RQP + ∠z = 180o (linear pair) 50o + ∠z = 180o ∠z = 180o – 50o = 130o ∴ ∠x = 130o ∠y = 130o ∠z = 130o (iii) In ΔPMN ∠NPM + ∠NMP + ∠MNP = 180° [Sum of all the angles of a triangle is 180°] 30° + 90° + ∠z = 180° ∠z = 180°-120° = 60° ∠y = ∠z = 60° [opposite angles are equal in a parallelogram] ∠z = 180°-120° [sum of the adjacent angles is equal to 180° in a parallelogram] ∠z = 60° ∠z + ∠LMN = 180° [sum of the adjacent angles is equal to 180° in a parallelogram] 60° + 90°+ ∠x = 180° ∠x = 180°-150° ∠x = 30° ∴ ∠x = 30o ∠y = 60o ∠z = 60o (iv) ∠x = 90° [vertically opposite angles are equal] In ΔDOC ∠x + ∠y + 30° = 180° [Sum of all the angles of a triangle is 180°] 90° + 30° + ∠y = 180° ∠y = 180°-120° ∠y = 60° ∠y = ∠z = 60° [alternate interior angles are equal] ∴ ∠x = 90o ∠y = 60o ∠z = 60o (v) ∠x + ∠POR = 180° [sum of the adjacent angles is equal to 180° in a parallelogram] ∠x + 80° = 180° ∠x = 180°-80° ∠x = 100° ∠y = 80° [opposite angles are equal in a parallelogram] ∠SRQ =∠x = 100° ∠SRQ + ∠z = 180° [Linear pair] 100° + ∠z = 180° ∠z = 180°-100° ∠z = 80° ∴ ∠x = 100o ∠y = 80o ∠z = 80o (vi) ∠y = 112° [In a parallelogram opposite angles are equal] ∠y + ∠VUT = 180° [In a parallelogram sum of the adjacent angles is equal to 180°] ∠z + 40° + 112° = 180° ∠z = 180°-152° ∠z = 28° ∠z =∠x = 28° [alternate interior angles are equal] ∴ ∠x = 28o ∠y = 112o ∠z = 28o |
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