1.

The following is the probability distribution of X :X = x-3-2-10123P(X = x)0.050.10.150.200.250.150.1Find the probability that (i) X is positive (ii) X is non-negative (iii) X is odd (iv) X is even.

Answer»

(i) P(X is positive) 

= P(X = 1) + P(X = 2) + P(X = 3) 

= 0.25 + 0.15 + 0.1 

= 0.50 

(ii) P(X is non-negative) 

= P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) 

= 0.20 + 0.25 + 0.15 + 0.1 

= 0.70 

(iii) P(X is odd) 

= P(X = -3) + P(X = -1) + P(X = 1) + P(X = 3)

= 0.05 + 0.15 + 0.25 + 0.1 

= 0.55 

(iv) P(X is even) 

= P(X = -2) + P(X = 0) + P(X = 2) 

= 0.10 + 0.20 + 0.15 

= 0.45.



Discussion

No Comment Found

Related InterviewSolutions